A) 0.7
B) 0.28
C) 0.3
D) 0.4
Correct Answer: C
Solution :
[c] As given \[P(A)=0.6,P(B)=0.3\] and \[P(A\cap B)=0.2\] \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[=0.6+0.3-0.2=0.9-0.2=0.7\] So, P (neither in A nor in B) \[=1-P(A\cup B)\] \[=1-0.7=0.3\]You need to login to perform this action.
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