A) \[\frac{1}{2}\]
B) \[\frac{1}{12}\]
C) \[\frac{1}{60}\]
D) \[\frac{1}{120}\]
Correct Answer: D
Solution :
[d] Probability of \[A=\frac{1}{6}\] Probability of \[B=\frac{1}{5}\] Probability of \[C=\frac{1}{4}\] Hence, required probability \[=\frac{1}{6}\times \frac{1}{5}\times \frac{1}{4}\] \[=\frac{1}{120}\]You need to login to perform this action.
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