A) \[0.00003\]
B) \[0.90\]
C) \[0.99997\]
D) \[0.90307\]
Correct Answer: C
Solution :
[c] Since, Probabilities of failure for engines A,B and C P(A), P[b] and P[c] are 0.03, 0.02 and 0.05 respectively. The aircraft will crash only when all the three engine fail. So, probability that it crashes \[=P(A).P(B).P(C)\] \[=0.03\times 0.02\times 0.05\] \[=0.00003\] Hence, the probability that the aircraft will not Crash \[=1-0.00003\] \[=0.99997\]You need to login to perform this action.
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