A) \[\frac{6}{31}\]
B) \[\frac{10}{31}\]
C) \[\frac{13}{62}\]
D) \[\frac{17}{62}\]
Correct Answer: B
Solution :
[b] Total no. of students in four schools \[=12+20+13+17=62.\] Now, one students is selected at random. \[\therefore \] Total outcomes \[{{=}^{62}}{{C}_{1}}\] Now, no, of students in school \[{{B}_{2}}=20.\] No. of ways to select a student form \[{{B}_{2}}{{=}^{20}}{{C}_{1}}.\] \[\therefore \] Required probability \[=\frac{{{20}_{{{C}_{1}}}}}{{{62}_{{{C}_{1}}}}}=\frac{20}{62}=\frac{10}{31}\]You need to login to perform this action.
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