A) 1/2
B) 3/4
C) 1/3
D) None of these
Correct Answer: A
Solution :
[a] Let P [a] = Probability that a randomly selected student likes tea = 0.3. Let \[P({{A}_{2}})=\] Probability that a randomly selected student does not like tea = 1 - 0.3 = 0.7. Let P [b] = Probability that a randomly selected student likes coffee = 0.2 \[\therefore P({{A}_{2}}\cap B)=P(B)-P(A\cap B)=0.2-0.1=0.1\] Now we have to find \[P({{A}_{2}}/B)=P({{A}_{2}}\cap B)/p(B)=0.1/0.2=1/2\]
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