A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{6}\]
D) \[\frac{5}{6}\]
Correct Answer: B
Solution :
[b] Favourable ways \[=3!\left( 1-\frac{1}{1!}+\frac{1}{2!}-\frac{1}{3!} \right)=2\] Total ways = 3! \[\therefore \] Required probability \[=\frac{2}{3!}=\frac{1}{3}\]You need to login to perform this action.
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