A) \[P(B/A)=P(B)-P(A)\]
B) \[P(A'\cup B')=P(A')+P(B')\]
C) \[P(A\cap B)=P(A')P(B')\]
D) None of these
Correct Answer: D
Solution :
[d] Given \[P(A)+P(B)-P(A)P(B)=P(A\cup B)\]comparing with \[P(A)+P(B)-P(A\cap B)=P(A\cup B)\] we get \[P(A\cap B)=P(A).P(B)\] \[\therefore \] A and B independent events.You need to login to perform this action.
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