A) \[\frac{9m}{8N+m}\]
B) \[\frac{9m}{8N-m}\]
C) \[\frac{9m}{8m-N}\]
D) \[\frac{9m}{8m+N}\]
Correct Answer: A
Solution :
[a] \[{{E}_{1}}:\] Coin is fair, \[{{E}_{2}}:\] coin is biased, a second toss shows tail. \[P({{E}_{1}}/A)=\frac{P(A/{{E}_{1}})P({{E}_{1}})}{P(A/{{E}_{1}})P({{E}_{1}})+P(A/{{E}_{1}})P({{E}_{2}})}\] \[=\frac{\frac{m}{N}.\frac{1}{2}.\frac{1}{2}}{\frac{m}{N}.\frac{1}{2}.\frac{1}{2}+\frac{N-m}{N}.\frac{2}{3}.\frac{1}{3}}=\frac{9m}{8N+m}\]You need to login to perform this action.
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