A) \[\frac{3}{4}\]
B) \[\frac{1}{2}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: A
Solution :
[a] \[P({{E}_{1}})=\frac{1}{2},P({{E}_{2}})=\frac{1}{3}andP({{E}_{3}})=\frac{1}{4};\] \[P({{E}_{1}}U{{E}_{2}}U{{E}_{3}})=1-P(\overline{{{E}_{1}}})P(\overline{{{E}_{2}}})P(\overline{{{E}_{3}}})\] \[=1-\left( 1-\frac{1}{2} \right)\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)=\frac{3}{4}\]You need to login to perform this action.
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