A) \[\frac{28}{256}\]
B) \[\frac{219}{256}\]
C) \[\frac{128}{256}\]
D) \[\frac{37}{256}\]
Correct Answer: A
Solution :
[a] Mean \[=np=4\] and variance \[=npq=2\] \[\therefore p=q=\frac{1}{2}\,\,and\,\,n=8\] \[\therefore \]P (2 success) \[=\,{{\,}^{8}}{{C}_{2}}{{\left( \frac{1}{2} \right)}^{6}}{{\left( \frac{1}{2} \right)}^{2}}=\frac{28}{{{2}^{8}}}=\frac{28}{256}\]
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