A) \[1/4\]
B) \[1/3\]
C) \[2/3\]
D) None of these
Correct Answer: B
Solution :
[b] Consider the following events: A: Father has at least one boy B: Father has 2 boys and one girl Then, A=one boy and 2 girls, 2 boys and one girl, 3 boys and no girl \[A\cap B=2\]boys and one girl now, the required probability is \[P(A/B)=\frac{P(A\cap B)}{P(A)}=\frac{1}{3}.\]
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