| X: | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| P(x) | 0 | 2p | 2p | 3p | \[{{p}^{2}}\] | \[2{{p}^{2}}\] | \[7{{p}^{2}}\] | 2p |
A) \[\frac{1}{10}\]
B) -1
C) \[\frac{3}{10}\]
D) None
Correct Answer: A
Solution :
[a] \[\Sigma p(x)=1\Rightarrow 9p+10{{p}^{2}}=1\] \[\Rightarrow 10{{p}^{2}}+9p-1=0\Rightarrow p=-1or\frac{1}{10}\] \[\therefore p=\frac{1}{10}\]
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