A) \[\frac{1}{2}\]
B) 1
C) \[\frac{1}{4}\]
D) 2
Correct Answer: B
Solution :
[c] Lets define the events as probability of getting project copy [a] = p Probability of getting blue pen [b] = q 0Probability of getting black pen [c] = 1/2 Then \[P(AC\overline{B})+p(AC\overline{B})+p(ABC)=\frac{1}{2}\] \[p.q.\frac{1}{2}+p.\frac{1}{2}(1-q)+p.q.\frac{1}{2}=\frac{1}{2}\] \[\therefore pq+p-pq+pq=1\] \[\therefore p(1+q)=1\]You need to login to perform this action.
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