JEE Main & Advanced Mathematics Probability Question Bank Self Evaluation Test - Probability-II

  • question_answer
    In an organization number of women are \[\mu \]times than that of men. If n things are distributed among them and the probability that the number of things Received by men are odd is\[\frac{1}{2}-{{\left( \frac{1}{2} \right)}^{n+1}}\], then \[\mu \] equal to

    A) 1

    B) 2

    C) 3

    D) \[\frac{1}{4}\]

    Correct Answer: C

    Solution :

    [c] If p and q probabilities that a thing goes to a man and woman respectively, then \[p=\frac{1}{1+\mu },q=\frac{\mu }{1+\mu }\] Now, given probability \[{{=}^{n}}{{C}_{1}}{{q}^{n-1}}p{{+}^{n}}{{C}_{3}}{{q}^{n-3}}{{p}^{3}}{{+}^{n}}{{C}_{5}}{{q}^{n-1}}{{p}^{5}}+....\]


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