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JEE Main & Advanced Mathematics Probability Question Bank Self Evaluation Test - Probability-II

  • question_answer
    Let \[0<P(A)<1,0<P(B)<1\] and \[P(A\cup B)=P(A)+P(B)-P(A)P(B,)\] then:

    A) \[P(B/A)=P(B)-P(A)\]

    B) \[P(A'\cup B')=P(A')+P(B')\]

    C) \[P(A\cap B)=P(A')P(B')\]

    D) None of these

    Correct Answer: D

    Solution :

    [d] Given \[P(A)+P(B)-P(A)P(B)=P(A\cup B)\]comparing with \[P(A)+P(B)-P(A\cap B)=P(A\cup B)\] we get \[P(A\cap B)=P(A).P(B)\] \[\therefore \] A and B independent events.


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