A) 2/19
B) 19/100
C) 1/50
D) None of these
Correct Answer: A
Solution :
[a] Let the number selected by xy. Then \[x+y=9,0\le x,y\le 9\] and \[xy=0\Rightarrow x=0,y=9\]or \[y=0,x=9\] \[P({{x}_{1}}=9/{{x}_{2}}=0)=\frac{P({{x}_{1}}=9\cap {{x}_{2}}=0)}{P({{x}_{2}}=0)}\] Now, \[P({{x}_{2}}=0)=\frac{19}{100}\] and \[P({{x}_{1}}=9\cap {{x}_{2}}=0)=\frac{2}{100}\] \[\Rightarrow P({{x}_{1}}=9/{{x}_{2}}=0)=\frac{2/100}{19/100}=\frac{2}{19}.\]
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