A) \[-\frac{4}{3}\]
B) \[\frac{4}{3}\]
C) \[\frac{8}{15}\]
D) \[\frac{4}{15}\]
Correct Answer: B
Solution :
[b] \[2\Delta =(a-b+c)(a+b+c)\] \[\Rightarrow 2\Delta =4(s-b)(s-c)\] \[\Rightarrow 2=\sqrt{\frac{s(s-a)}{(s-b)(s-c)}}\Rightarrow \tan \frac{A}{2}=\frac{1}{2}\] \[\therefore \tan A=\frac{2\times \frac{1}{2}}{1-\frac{1}{4}}=\frac{4}{3}\]You need to login to perform this action.
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