A) \[2500\sqrt{3}\] meters
B) \[2500\] meters
C) \[500\sqrt{3}\] meters
D) None of these
Correct Answer: A
Solution :
[a] \[(H-h)cot15{}^\circ =(H+h)cot45{}^\circ \] or \[H=\frac{h(cot15{}^\circ +1)}{(cot15{}^\circ -1)}\] Since \[h=2500\]and substitute \[\cot 15{}^\circ =2+\sqrt{3},\] we get \[H=2500\sqrt{3}\]You need to login to perform this action.
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