A) \[\frac{n}{n-1}\]
B) \[\frac{n-1}{n}\]
C) \[\frac{n+1}{n}\]
D) \[n\]
Correct Answer: A
Solution :
[a] \[\frac{1}{f}=\frac{2}{{{f}_{e}}}+\frac{2}{{{f}_{m}}}\] \[{{f}_{m}}=\frac{R}{2}\text{ }{{f}_{m}}=0\] \[\frac{1}{{{f}_{e}}}=\frac{n-1}{R}\text{ }{{f}_{e}}=\frac{n-1}{R}\text{ }{{f}_{2}}=\frac{R}{2n}\] \[{{f}_{1}}=\frac{R}{2\left( n-1 \right)}\text{ Ratio}\frac{{{f}_{1}}}{{{f}_{2}}}=\frac{n}{n-1}\]You need to login to perform this action.
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