A) 6.1 rad
B) 3.2 rad
C) 1.5 rad
D) 0.2 rad
Correct Answer: C
Solution :
[c] Magnifying power of telescope, \[MP=\frac{\beta \left( \text{angle subtended by image at eye piece} \right)}{\alpha \left( \text{angle subtended by object on objective} \right)}\]Also, \[MP=\frac{{{f}_{0}}}{{{f}_{e}}}=\frac{150}{5}=30\text{ }\alpha =\frac{50}{1000}=\frac{1}{20}rad\] \[\therefore \,\,\,\,\,\beta =\theta =MP\times \alpha =30\times \frac{1}{20}=\frac{3}{2}=1.5rad\]You need to login to perform this action.
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