A) \[{{S}_{2}}O_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}~\]
B) \[SO_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}~\]
C) \[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}~\]
D) \[{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}<SO_{3}^{2-}~\]
Correct Answer: C
Solution :
[c] In \[SO_{3}^{^{2-}}\] \[x+3\left( -2 \right)=-2;x=+4\] In \[{{S}_{2}}O_{6}^{2-}\] \[2x+4\left( -2 \right)=-2\] \[2x-8=-2\] \[2x=6;\,\,x=+3\] In \[{{S}_{2}}O_{6}^{2-}\] \[2x+6\left( -2 \right)=-2\] \[2x=10;\text{ }\,\,x=+5\] hence the correct order is \[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}\]
You need to login to perform this action.
You will be redirected in
3 sec
