A) CO and\[C{{l}_{2}}\]
B) \[S{{O}_{\text{2}}}\] and \[C{{l}_{2}}\]
C) \[{{H}_{2}}S\] and\[B{{r}_{\text{2}}}\]
D) \[N{{H}_{3}}\] and \[S{{O}_{2}}\]
Correct Answer: B
Solution :
[b] \[S{{O}_{2}}\]bleaches by reduction, while chlorine bleaches colour of flowers by oxidation.
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