A) + 4 to + 2
B) + 5 to + 3
C) + 6 to + 3
D) + 7 to + 2
Correct Answer: C
Solution :
[c] \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+3S{{O}_{2}}+4{{H}_{2}}S{{O}_{4}}\to \] \[{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+3S{{O}_{3}}+4{{H}_{2}}O\] O.N. of chrominum changes from +6 to +3
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