A) 1
B) 2
C) 3
D) 4
Correct Answer: C
Solution :
[c] Calculating the oxidation state of nitrogen in given molecules; Oxidation state of N in \[N{{H}_{3}}\] is \[x+3\times (+1)=0\, or \,x=-3\] Oxidation state on N in \[HN{{O}_{3}}\] is \[1+x+3\times \left( -2 \right)=0\,or\,x=+5\] Oxidation state of N in \[Na{{N}_{3}}\] is \[+1+3x=0\text{ }or\,x=-\frac{1}{3}\] Oxidation state of N in \[M{{g}_{3}}{{N}_{2}}\]is \[3\times 2+2x=0\,or\,x=-3\] Thus 3 molecules (i.e. \[N{{H}_{3}},Na{{N}_{3}}\]and \[M{{g}_{3}}{{N}_{2}}\]have nitrogen in negative oxidation states.
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