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NEET Chemistry Redox Reactions / रेडॉक्स अभिक्रियाएँ Question Bank Self Evaluation Test - Redox Reactions

  • question_answer
    A compound of Xe and F is found to have 53.5% of Xe. What is oxidation number of Xe in this compound?

    A) - 4                               

    B) 0   

    C) +4                               

    D) +6

    Correct Answer: D

    Solution :

    [d] \[Xe=53.5%\,\therefore F=46.5%\] Relative number of atoms Xe \[=\frac{53.5}{131.2}=0.4\] and \[F=\frac{46.5}{19}=2.4\] Simple ratio Xe = 1 and F = 6 ; Molecular formula is \[Xe{{F}_{6}}\] O.N. of Xe is+6


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