| (i) \[PO_{4}^{3-}\] |
| (ii) \[S{{O}_{3}}\] |
| (iii) \[PO_{3}^{2-}\] |
| (iv) \[N{{H}_{3}}\] |
A) (i), (ii) and (iii)
B) Only (iii)
C) (i), (iii) and (iv)
D) (iii) and (iv)
Correct Answer: D
Solution :
[d] In (i) and (ii) both P and S are in highest oxidation state. In (iii) and (iv) ; P has oxidation state of+4 which can be oxidized to +5 state, while in case of \[N{{H}_{3}}\] nitrogen has oxidation state of -3 which can be oxidised.
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