A) \[N{{a}_{2}}O\]\[\]
B) \[SnC{{l}_{2}}\]
C) \[N{{a}_{2}}{{O}_{2}}\]
D) \[NaN{{O}_{2}}\]
Correct Answer: D
Solution :
[d] In \[N{{a}_{2}}O,SnC{{l}_{2}}\]and \[N{{a}_{2}}{{\text{O}}_{2}}\]central atom is either in lowest or highest oxidation state, so they can function either as an oxidizing .or a reducing agent but not both. However, the oxidation state of N in \[N{{a}_{2}}{{\text{O}}_{2}}\] is +3 which lies between its highest (+5) and lowest \[\left( -3 \right)\] values.
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