A) \[FeC{{l}_{3}}\] acts as an oxidising agent
B) Both \[{{H}_{2}}S\] are \[FeC{{l}_{3}}\] are oxidized
C) \[FeC{{l}_{3}}\] is oxidised while \[{{H}_{2}}S\] is reduced
D) \[{{H}_{2}}S\] acts as an oxidising agent.
Correct Answer: A
Solution :
[a] In \[2FeC{{l}_{3}}+{{H}_{2}}S\to 2FeC{{l}_{2}}+2HCl+S\] O.N. of S changes from -2 to 0 (hence oxidised) O.N. of Fe changes from +3 to +2 hence reduced.
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