A) \[2PhCHO\xrightarrow{Al{{(OEt)}_{3}}}PhCOOC{{H}_{2}}Ph\]
B)
C) \[NaH+{{H}_{2}}O\xrightarrow{{}}NaOH+{{H}_{2}}\]
D) All of the above.
Correct Answer: C
Solution :
[c] [a] and [b] are disproportionation reactions. [c] is an oxidation reaction. \[2{{H}^{-}}\xrightarrow{{}}{{H}_{2}}+2{{e}^{-}}\]
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