A) \[-{{\log }_{2}}(1-x)\]
B) \[-{{\log }_{2}}(x)\]
C) 0
D) 1
Correct Answer: A
Solution :
[a] Let \[y=1-{{2}^{-x}}or{{2}^{-x}}=1-y\] or \[-x={{\log }_{2}}(1-y)or{{f}^{-1}}(x)=g(x)=-lo{{g}_{2}}(1-x).\]
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