A) \[D(f+g)=R-[-2,0)\]
B) \[D(f+g)=R-[-1,0)\]
C) \[R(f)\cap R(g)=\left[ -2,\frac{1}{2} \right]\]
D) None of these
Correct Answer: D
Solution :
[d] \[D(f)=R;D(g)=R-[-1,0)\] \[\therefore D(f+g)=D(f)\cap D(g)=R\cap (R-[-1,0)=R\cap [-1,0)\]\[R(f)=\left[ -\frac{1}{2},\frac{1}{2} \right];R(g)=R-\{0\}\] \[\therefore \,\,\,\,R(f)\cap R(g)=\left[ -\frac{1}{2},\frac{1}{2} \right]\cap (R-\{0\})\] \[=\left[ -\frac{1}{2},\frac{1}{2} \right]-\{0\}\]You need to login to perform this action.
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