A) 0
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
[c] Let \[f(x)=ax+b\] (1) \[\Rightarrow f(ax+b+x)=x+ax+b\] \[\Rightarrow f((a+1)x+b)=(a+1)x+b\] Replace \[(a+1)x+b\]by, y, we have \[\Rightarrow f(y)=(a+1)\left( \frac{y-b}{a+1} \right)+b\] Or \[f(x)=(a+1)\left( \frac{x-b}{x+1} \right)+b\] \[\therefore \] Required no, of linear functions is 2.You need to login to perform this action.
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