A) 0
B) 1
C) -1
D) \[\pi \]
Correct Answer: A
Solution :
[a] \[(ho(gof))(x)=h\{g\{f(x)\}\}\] \[=h\{tan{{x}^{2}}\}=log\{tan{{x}^{2}}\}\] \[\therefore Atx=\sqrt{\frac{\pi }{4}}\Rightarrow (ho(gof))(x)=logtan\frac{\pi }{4}\] \[=\log 1=0\]You need to login to perform this action.
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