JEE Main & Advanced Mathematics Functions Question Bank Self Evaluation Test - Relation and Functions-II

  • question_answer
    \[f(x)=\left| x-1 \right|,f:{{R}^{+}}\to R\] and \[g(x)={{e}^{x}},\] \[g:[(-1,\infty )\to R].\] If the function fog (x) is defined, then its domain and range respectively are

    A) \[(0,\infty )\,\,and\,\,[0,\infty )\]

    B) \[[-1,\infty )\,\,and\,\,[0,\infty )\]

    C) \[[-1,\infty )and\left[ 1-\frac{1}{e},\infty  \right)\]

    D) \[[-1,\infty )and\left[ \frac{1}{e}-1,\infty  \right)\]

    Correct Answer: B

    Solution :

    [b] \[f(x)=\left| x-1 \right|=\left\{ \begin{matrix}    1-x,\,0<x<1  \\    x-1,\,x\ge 1  \\ \end{matrix} \right.\] \[g(x)={{e}^{x}},x\ge -1\] \[(fog)(x)=\left\{ \begin{matrix}    1-g(x),\,0<g(x)<1i.e.-1\le x<0  \\    g(x)-1,\,g(x)\ge 1i.e.0\le x  \\ \end{matrix} \right.\] \[=\left\{ \begin{matrix}    1-{{e}^{x}},-1\le x<0  \\    {{e}^{x}}-1,x\ge 0  \\ \end{matrix} \right.\] \[\therefore \]Domain \[=[-1,\infty )\] fog is decreasing in \[[-1,0)\] and increasing in \[[0,\infty )\] \[fog(-1)=1-\frac{1}{e}\] and \[fog(0)=0\] As \[x\to \infty ,fog(x)\to \infty ,\] \[\therefore \] range \[=[0,\infty )\]


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