A) \[[2,3]\]
B) \[[-2,4]\]
C) \[[-2,2]\cup [3,4]\]
D) \[[-2,1]\cup [2,4]\]
Correct Answer: C
Solution :
[c] \[f(x)=\sqrt{(x-2)(x-3)}+\sqrt{-(x-4)(x+2)}\] The first part is real outside (2, 3) and the second is real in [-2, 4] so that the domain is \[[-2,2]\cup [3,4].\]You need to login to perform this action.
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