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JEE Main & Advanced Physics Semiconducting Devices Question Bank Self Evaluation Test - Semiconductor Electronics: Materials, Devices and Simple Circuits

  • question_answer
    In a triode, \[{{g}_{m}}=2\times {{10}^{-3}}oh{{m}^{-1}};\] \[\mu =42;\] resistance of load, \[R=50\] kilo ohm. The voltage amplification obtained from this triode will be

    A)  \[30.42\]

    B)  \[29.57\]

    C)  \[28.18\]

    D)  \[27.15\]

    Correct Answer: B

    Solution :

    [b] \[{{A}_{v}}=\frac{\mu R}{{{r}_{p}}+R}=\frac{\mu R}{(\mu /{{g}_{m}})+R}\] \[=\frac{42\times (50\times {{10}^{3}})}{42/(2\times {{10}^{-3}})+50\times {{10}^{3}}}=29.57\]


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