A) \[3.2\times {{10}^{20}}\,{{m}^{-3}}\]
B) \[8.49\times {{10}^{26}}\,{{m}^{-3}}\]
C) \[6.2\times {{10}^{31}}\,{{m}^{-3}}\]
D) None
Correct Answer: B
Solution :
[b] If M is the molar mass and \[\rho \] is the density then volume of one mole \[V=\frac{M}{\rho }.\] The number of atoms per unit volume \[=\frac{{{N}_{A}}}{V}=\frac{{{N}_{A}}}{M/\rho }=\frac{{{N}_{A}}\rho }{M}=\frac{(6.02\times {{10}^{23}})\times (8.96)}{63.54}\] \[=8.49\times {{10}^{22}}\,\,c{{m}^{-3}}=8.49\times {{10}^{28}}{{m}^{-3}}\] As each copper (monovalent) atom has one electron, so number of electrons per unit volume \[=8.49\times {{10}^{26}}{{m}^{-3}}\]
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