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JEE Main & Advanced Physics Semiconducting Devices Question Bank Self Evaluation Test - Semiconductor Electronics: Materials, Devices and Simple Circuits

  • question_answer
    The current gain in the common emitter mode of a transistor is 10. The input impedance is \[20\,k\,\Omega \]and load of resistance is \[100\,k\,\Omega \]. The power gain is

    A)  \[300\]

    B)  \[500\]

    C)  \[200\]

    D)  \[100\]

    Correct Answer: B

    Solution :

    [b] The power gain in case of CE amplifier, Power gain \[={{\beta }^{2}}\times \] Resistance gain \[={{\beta }^{2}}\times \frac{{{R}_{o}}}{{{R}_{i}}}={{(10)}^{2}}\times 5=500.\] 


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