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JEE Main & Advanced Physics Semiconducting Devices Question Bank Self Evaluation Test - Semiconductor Electronics: Materials, Devices and Simple Circuits

  • question_answer
    A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of \[800\,\Omega \] is connected in the collector circuit and the voltage drop across it is\[0.8\text { } V\]. If the current amplification factor is \[0.96\] and the input resistance of the circuit is \[192\Omega, \]the voltage gain and the power gain of the amplifier will respectively be:

    A)  \[4,\,\,3.84\]

    B)  \[3.69,\,\,3.84\]

    C)  \[4,\,\,4\]

    D)  \[4,\,\,3.69\]

    Correct Answer: A

    Solution :

    [a] \[{{P}_{V}}={{A}_{V}}\alpha =4\times 0.96=3.84\]


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