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JEE Main & Advanced Physics Semiconducting Devices Question Bank Self Evaluation Test - Semiconductor Electronics: Materials, Devices and Simple Circuits

  • question_answer
    The input resistance of a silicon transistor is\[100\text{ }W\]. Base current is changed by \[40\mu A\] which results in a change in collector current by \[2\text{ }mA\]. This transistor is used as a common emitter amplifier with a load resistance of \[4\,K\Omega \]. The voltage gain of the amplifier is:

    A)  \[2000\]

    B)  \[3000\]

    C)  \[4000\]

    D)  \[1000\]

    Correct Answer: A

    Solution :

    [a] Voltage gain \[({{A}_{V}})=\frac{{{V}_{out}}}{{{V}_{in}}}=\frac{{{I}_{out}}}{{{I}_{in}}}\times \frac{{{R}_{out}}}{{{R}_{in}}}\] \[{{A}_{V}}=\frac{2\times {{10}^{-3}}}{40\times {{10}^{-6}}}\times \frac{4\times {{10}^{3}}}{100}=2\times 100=2000\]


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