JEE Main & Advanced Physics Semiconducting Devices Question Bank Self Evaluation Test - Semiconductor Electronics: Materials, Devices and Simple Circuits

  • question_answer
    In the following common emitter configuration an NPN transistor with current gain \[\beta =100\] is used. The output voltage of the amplifier will be

    A)  \[10\,\,mV\]

    B)  \[0.1\text{ }V\]

    C)  \[1.0\text{ }V\]

    D)  \[10\text{ }V\]

    Correct Answer: C

    Solution :

    [c] Voltage gain, \[\frac{{{V}_{0}}}{{{V}_{i}}}=\beta \frac{{{R}_{2}}}{{{R}_{1}}}\]  or  \[{{V}_{0}}=\left[ \beta \frac{{{R}_{2}}}{{{R}_{1}}} \right]\times {{V}_{i}}\] \[=\left[ 100\times \frac{10}{1} \right]\times 1\times {{10}^{-3}}=1V.\]


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