A) \[4:1\]
B) \[2:1\]
C) \[1:2\]
D) \[1:4\]
Correct Answer: D
Solution :
[d] \[\frac{{{J}_{1}}}{{{J}_{2}}}=\frac{AT_{1}^{2}{{e}^{-{{W}_{1}}/k{{T}_{1}}}}}{AT_{2}^{2}{{e}^{-{{W}_{2}}/k{{T}_{2}}}}}\] \[={{\left(\frac{{{T}_{1}}}{{{T}_{2}}}\right)}^{2}}{{e}^{-\frac{{{W}_{1}}}{k{{T}_{1}}}+\frac{{{W}_{2}}}{k{{T}_{2}}}}}={{\left(\frac{1}{2} \right)}^{2}}{{e}^{0}}=\frac{1}{4}\]You need to login to perform this action.
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