A) 1
B) 2
C) 3
D) None of these
Correct Answer: B
Solution :
[b]\[S=\frac{a(1-{{r}^{n}})}{1-r},P={{a}^{n}}.{{r}^{\frac{n(n-1)}{2}}}\] \[R=\frac{1}{a}+\frac{1}{ar}+\frac{1}{a{{r}^{2}}}+.....n\,\,terms=\frac{1-{{r}^{n}}}{a(1-r){{r}^{n-1}}}\] \[{{S}^{n}}={{R}^{n}}{{P}^{k}}\Rightarrow {{\left( \frac{S}{R} \right)}^{n}}={{P}^{k}}\] \[\Rightarrow {{({{a}^{2}}\,{{r}^{n-1}})}^{n}}={{P}^{k}}\Rightarrow {{P}^{2}}={{P}^{k}}\Rightarrow k=2\]
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