JEE Main & Advanced Mathematics Sequence & Series Question Bank Self Evaluation Test - Sequences and Series

  • question_answer
    The value of \[\sum\limits_{n=1}^{10}{\sum\limits_{m=1}^{10}{({{m}^{2}}+{{n}^{2}})}}\] equals

    A) 4235

    B) 5050

    C) 7700

    D) None of these

    Correct Answer: C

    Solution :

    [c]  \[\sum\limits_{n=1}^{10}{\sum\limits_{m=1}^{10}{({{m}^{2}}+{{n}^{2}})}}\] \[=\sum\limits_{n=1}^{10}{[({{1}^{2}}+{{n}^{2}})+({{2}^{2}}+{{n}^{2}})+....+({{10}^{2}}+{{n}^{2}})]}\] \[=10[{{(1)}^{2}}+{{(2)}^{2}}+....+{{(10)}^{2}}]+10[{{(1)}^{2}}\]                         \[+{{(2)}^{2}}+....+{{(10)}^{2}}]\] \[=\frac{20.10.11.21}{6}=7700\]


You need to login to perform this action.
You will be redirected in 3 sec spinner