A) \[a=b+c\]
B) \[a=bc\]
C) \[b=ac\]
D) \[c=ab\]
Correct Answer: B
Solution :
[b] \[a=1+10+{{10}^{2}}+....+{{10}^{54}}\] \[=\frac{{{10}^{55}}-1}{10-1}=\frac{{{10}^{55}}-1}{{{10}^{5}}-1}.\frac{{{10}^{5}}-1}{10-1}=bc\]
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