A) \[\frac{1}{3}\]
B) 3
C) \[\frac{1}{2}\]
D) 2
Correct Answer: B
Solution :
[b] \[(1-p)(1+3x+9{{x}^{2}}+27{{x}^{3}}+81{{x}^{4}}+243{{x}^{5}})\] \[=1-{{p}^{6}}\] \[\Rightarrow (1+3x+9{{x}^{2}}+27{{x}^{3}}+81{{x}^{4}}+243{{x}^{5}})=\frac{1-{{p}^{6}}}{1-p}\]\[\Rightarrow (1+3x+9{{x}^{2}}+27{{x}^{3}}+81{{x}^{4}}+243{{x}^{5}})\] \[=1+p+{{p}^{2}}+{{p}^{3}}+{{p}^{4}}+{{p}^{5}}\] Comparing we get \[p=3x\] or \[p/x=3\]You need to login to perform this action.
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