A) \[\phi \]
B) P?
C) m
D) P
Correct Answer: A
Solution :
[a]Since \[\mu \]is universal set And \[P\subseteq \mu ,\,\,P-\mu =\phi \] and \[\mu -P=P'\] So, \[(P-\mu )\cup (\mu -P)=\phi \cup P'=P'\] Now, \[P\cap \{P-\mu )\cup (\mu -P\}=P\cap P'=\phi \]You need to login to perform this action.
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