A) 4.42
B) 4.00
C) 3.42
D) 5.42
Correct Answer: A
Solution :
[a] Given \[{{\pi }_{ob}}=10.8atm\] \[{{\pi }_{nor}}=CRT=0.10\times 0.0821\times 298=2.446\] now experimental value of (i) \[=\frac{Observed\text{ }osmotic\text{ }pressure}{Normal\text{ }osmotic\text{ }pressure}\] \[=\frac{10.8}{2.446}=4.42\]You need to login to perform this action.
You will be redirected in
3 sec