A) 152 torr
B) 608 torr
C) 760 torr
D) 547 torr
Correct Answer: B
Solution :
[b] Moles of solute \[=\frac{28}{28}=1;\] moles of water \[=\frac{100-28}{18}=4\] V.P. of solution \[=P_{{{H}_{2}}O}^{{}^\circ }\times {{X}_{{{H}_{2}}O}}=760\times \frac{4}{5}=608\,torr\]You need to login to perform this action.
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