A) 0.137
B) 0.237
C) 0.435
D) 0.205
Correct Answer: B
Solution :
[b] \[{{P}_{A}}=P_{A}^{{}^\circ }\times {{x}_{A}}\]= total pressure \[\times {{y}_{A}}\] \[{{P}_{B}}=P_{B}^{{}^\circ }\times {{x}_{B}}\] pressure \[\times {{y}_{B}}\] where x and y represents mole fraction in liquid and vapour phase respectively. \[\frac{P_{B}^{{}^\circ }{{x}_{B}}}{P_{A}^{{}^\circ }{{x}_{A}}}=\frac{{{y}_{B}}}{{{y}_{A}}};\frac{P_{B}^{{}^\circ }(1-{{x}_{A}})}{P_{A}^{{}^\circ }{{x}_{A}}}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\] on putting values \[\frac{119(1-0.50)}{37\times 0.50}=\frac{1-{{y}_{A}}}{{{y}_{A}}}\] on solving \[{{y}_{A}}=0.237\]You need to login to perform this action.
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